Pressure-flow table for a K160 sprinkler. Every value is calculated from Q = K√P, with Q in litres per minute and P in bar.

Metric K160 corresponds to K11.2 in US units (gpm/psi½): NFPA 13 Table 7.2.2.1 gives K160 as the metric nominal value for K11.2, with a permitted range of 159–166 L/min/bar½ (conversion factor 14.4). Typical application: High hazard process and storage; CMDA applications.

Pressure-flow table (K160)

Pressure (bar)Flow (L/min)Flow (L/s)
0.50113.11.89
0.70133.92.23
1.00160.02.67
1.40189.33.16
1.75211.73.53
2.00226.33.77
2.50253.04.22
3.00277.14.62
3.50299.34.99
4.00320.05.33
5.00357.85.96
6.00391.96.53
7.00423.37.06
8.00452.57.54
10.00506.08.43
12.00554.39.24

Required pressure at common design combinations

The table below shows the pressure a K160 sprinkler requires for a given density and coverage area. The calculation: required flow = density × coverage area; required pressure = (flow / K)².

Density (mm/min)Coverage area (m²)Required flow (L/min)Required pressure (bar)
2.2512.027.00.03
5.0012.060.00.14
7.5012.090.00.32
10.009.090.00.32
12.509.0112.50.49
12.507.492.50.33

Note: in EN 12845 the maximum area per sprinkler is 21 m² for LH, 12 m² for OH and 9 m² for HHP and HHS (Table 19). The K-factor is selected by hazard class (Table 37a): K57 for LH, K80 or K115 for OH, and for HHP and HHS ceiling sprinklers K80, K115 or K160 at densities ≤ 10 mm/min and K115 or K160 above 10 mm/min. The minimum sprinkler pressure is 0.70 bar for LH, 0.35 bar for OH and 0.50 bar for HHP and HHS (clause 13.4.4). NFPA 13 requires at least 0.5 bar (7 psi) at any sprinkler (clause 28.2.4.11.1). Some of the combinations in the table therefore cannot be used with this K-factor under EN 12845.

How to use it

  1. Take the design density (mm/min) from the hazard class.
  2. Find the coverage area (m²) from the sprinkler layout.
  3. Calculate the required flow by multiplying them.
  4. Read the required pressure from the table above, or calculate P = (Q/K)².
  5. Compare the result with the minimum sprinkler pressure the standard requires; if it is lower, use the minimum and recalculate the flow.

The table gives the pressure at the sprinkler inlet. In the hydraulic calculation, pipe friction loss, fitting equivalent lengths and elevation are added on top; the pressure at the system entry point is their sum.

Points to watch

Frequently Asked Questions

How much does a K160 sprinkler flow at 4 bar?

320.0 L/min from Q = K√P. That value corresponds to the pressure at the sprinkler inlet.

What is the US-unit equivalent of metric K160?

K11.2. NFPA 13 Table 7.2.2.1 gives K160 as the metric nominal value for K11.2. The conversion factor is 14.4, and which unit a catalogue uses must always be confirmed.

Can the sprinkler operate below the lowest pressure in the table?

No. NFPA 13 clause 28.2.4.11.1 sets a minimum operating pressure of 0.5 bar (7 psi) for any sprinkler; where the listing specifies a higher minimum, that governs (clause 28.2.4.11.2). EN 12845 clause 13.4.4 also sets minimum pressures by hazard class. For ESFR sprinklers the listed minimum operating pressure is especially binding.

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Standards & References

NFPA 13 (2025) Table 7.2.2.1, clause 28.2.4.11 · TS EN 12845+A2:2026 (EN 12845:2015+A2:2026) Table 19, Table 37a, clause 13.4.4 · EN 12259-1. Table values are calculated from Q = K√P; the manufacturer's approval document governs the product-specific minimum and maximum operating pressure.